# 150 Missing Number Series PDF for IBPS Clerk Prelims

Questions on **number series **are prevalent in most of the management aptitude exams. These questions are based on numerical sequences that follow a logical rule/ pattern based on elementary arithmetic concepts.

A particular series is given by which the pattern must be analyzed. You are then asked to predict the next number in the sequence following the same rule. Generally, there are three types of questions asked from the number series:

**A numerical series** is given in which a number is wrongly placed. You are asked to identify that particular wrong number.

A numerical series is given in which a specific number is missing. You are required to find out that missing number.

A complete numerical series is followed by an incomplete numerical series. You need to solve that incomplete numerical series in the same pattern in which the complete numerical series is given.

**How to solve Number series problems easily By Tricks**

13.2.15

Generally, two kinds of series are asked in the examination. One is based on numbers and the other based on alphabets.

Step 1: Observer is there any familiar numbers in the given series. Familiar numbers are primes numbers, perfect squares, cubes … which are easy to identify.

Step 2: Calculate the differences between the numbers. Observe the pattern in the differences. If the differences are growing rapidly it might be a square series, cube series, or multiplicative series. If the numbers are growing slowly it is an addition or subtraction series.

- It might be a double or triple series. Here every alternate number or every 3rd number form a series
- It might be a sum or average series. Here sum of two consecutive numbers gives a 3rd number. or an average of first two numbers give the next number

Step 3: Sometimes number will be multiplied and will be added another number So we need to check those patterns

TYPES OF NUMBER SERIES

I. Prime number Series :

Example (1) : 2,3,5,7,11,13, ………..

Answer: The given series is the prime number series. The next prime number is 17.

Example (2) :2,5,11,17,23,………..41.

Answer: The prime numbers are written alternately.

II. Difference Series :

Example (1): 2,5,8,11,14,17,………..,23.

Answer: The difference between the numbers is 3. (17+3 = 20)

Example (2): 45,38,31,24,17,………..,3.

Answer: The difference between the numbers is 7. (17-7=10). III. Multiplication Series:

Example (1) : 2,6,18,54,162,………,1458.

Answer: The numbers are multiplied by 3 to get next number. (162×3 = 486).

Example: (2) : 3,12,48,192,…………,3072.

Answer : The numbers are multiplied by 4 to get the next number. (192×4 =768).

IV. Division Series:

Example (1): 720, 120, 24, ………,2,1

Answer: 720/6=120, 120/5=24, 24/4=6, 6/3=2, 2/2=1.

Example (2) : 32, 48, 72, 108, ………., 243.

Answer: 2. Number x 3/2= next number. 32×3/2=48, 48×3/2=72, 72×3/2=108, 108×3/2=162.

V. n2 Series:

Example(1) : 1, 4, 9, 16, 25, ……., 49

Answer: The series is 12, 22, 32, 42, 52, …. The next number is 62=36;

Example (2) : 0, 4, 16, 36, 64, …….. 144.

Answer :The series is 02, 22, 42, 62, etc. The next number is 102=100.

VI. n2−1 Series :

Example : 0, 3, 8, 15, 24,35, 48, ……….,

Answer : The series is 12-1, 22-1, 32-1 etc. The next number is 82-1=63.

Another logic : Difference between numbers is 3, 5, 7, 9, 11, 13 etc. The next number is (48+15=63).

VII.n2+1 Series :

Example : 2, 5, 10, 17, 26, 37, ………., 65.

Answer : The series is 12+1, 22+1, 32+1 etc. The next number is 72+1=50.

VIII. n2+n Series (or) n2−n Series :

Example : 2, 6, 12, 20, …………, 42.

Answer : The series is 12+1, 22+2, 32+3, 42+4 etc. The next number = 52+5=30.

Another Logic : The series is 1×2, 2×3, 3×4, 4×5, The next number is 5×6=30.

Another Logic : The series is 22-2, 32-3, 42-4, 52-5, The next number is 62-6=30.

IX. n3 Series :

Example : 1, 8, 27, 64, 125, 216, ……… .

Answer : The series is 13, 23, 33, etc. The missing number is 73=343.

X. n3+n Series :

Example : 2, 9, 28, 65, 126, 217, 344, ………..

Answer : The series is 13+1, 23+1, 33+1, etc. The missing number is 83+1=513.

XI. n3−1 Series :

Example : 0, 7, 26, 63, 124, …………, 342.

Answer: The series is 13-1, 23-1, 33-1 etc The missing number is 63-1=215.

XII. n3+n Series :

Example : 2, 10, 30, 68, 130, ………….., 350.

Answer : The series is 13+1, 23+2, 33+3 etc The missing number is 63+6=222.

XIII. n3−n Series :

Example :0, 6, 24, 60, 120, 210, …………..,

Answer : The series is 13-1, 23-2, 33-3, etc. The missing number is 73-7=336.

Another Logic : The series is 0x1x2, 1x2x3, 2x3x4, etc. The missing number is 6x7x8=336.

XIV. n3+n2 Series :

Example : 2, 12, 36, 80, 150, …………,

Answer: The series is 13+12,23+22,33+32etc. The missing number is 63+62=252

XV. n3−n2 Series:

Example: 0,4,18,48,100,……………..,

Answer : The series is 13-12,23-22,33-32 etc. The missing number is 63-62=180

XVI. xy, x+y Series:

Example: 48,12,76,13,54,9,32,……………,

Answer :2. 4+8=12, 7+6=13, 5+4=9 .: 3+2=5

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